Infinite charges of magnitude $q$ each are lying at $x =1,\, 2,\, 4,\, 8…$ meter on $X$-axis. The value of intensity of electric field at point $x = 0$ due to these charges will be

The distance between a proton and electron both having a charge $1.6 \times {10^{ – 19}}\,coulomb$, of a hydrogen atom is ${10^{ – 10}}\,metre$. The value of intensity of electric field produced on electron due to proton will be

Two point charges $q_1\,(\sqrt {10}\,\,\mu C)$ and $q_2\,(-25\,\,\mu C)$ are placed on the $x-$ axis at $x = 1\,m$ and $x = 4\,m$ respectively. The electric field (in $V/m$ ) at a point $y = 3\,m$ on $y-$ axis is, [ take ${\mkern 1mu} {\mkern 1mu} \frac{1}{{4\pi {\varepsilon _0}}} = 9 \times {10^9}{\mkern 1mu} {\mkern 1mu} N{m^2}{C^{ – 2}}{\rm{ }}$ ]

Explain electric field and also electric field by point charge.

Two equal negative charges $-\, q$ each are fixed at the points $(0, a)$ and $(0, -a)$ on the $Y$ -axis. A positive charge $Q$ is released from rest at the point $(2a, 0)$ on the $X$ -axis. The charge $Q$ will :-